| Subject: RE: Could you
dummy-down your theories for me? Date: Tue, 6 Nov 2001 17:13:20 -0600 Dear
Paul, Unfortunately,
the only "simple" way to explain an overunity EM system is
still a way that would not make enough sense to you to enable
experimentation. But it
may help understand "what is going on" from a less-technical
description. Basically
you have to have a "free energy flow" (consider it an
"electrical wind", to be real simple).
Then the system must intercept and "catch" some of
that free-flowing energy wind, much like a windmill in the wind.
In that case, the system is free to take the energy it collects
and dissipate it in a load, to power it -- much like a windmill can
use the energy it captures from the free wind to rotate its blades and
power a pump that is pumping water. Now
at that point the simply analogies break down.
Suppose, e.g., that you had been taught only to build windmills
which would take half the energy they do catch, to rotate those blades
so they will catch no air. The
other half of the caught energy is used to power the losses and get
some also to the load to power it. Now
that would be an interesting windmill.
You could set it in the freely blowing wind, and the darn thing
would immediately turn its own blades so it caught no wind energy and
quit turning and pumping the load.
Then you would have to perform some strenuous work on those
blades to angle them again to catch some more wind energy -- but the
darn thing would still use more energy to turn those blades back to
nonrotating condition, than it output to run the pump that was pumping
the water. Well,
you will have to input at least as much energy to re-rotate the blades
into "energy-catching" mode, as was used to turn them back
in the first place. And
that's more than the energy you got out in the load.
So you would always have to keep inputting more energy, to
remake the "blade angle" position, than you can get out in
the load. That's
the way every electrical system out there is built, in terms as simple
as possible. Obviously
you've got to find a way to prevent the part of that crazily designed
windmill's operation where it re-rotates the blades so they do not
catch any wind energy. If
you can eliminate, e.g., half of that effect, then with an efficient
windmill that doesn't lose too much energy in its losses, you can get
more energy into that pump to pump water, than you yourself will have
to input. Understand, the
wind is inputting the rest of the energy. So
the "efficiency" of that machine may be, say, 60%.
That is, of the energy you input and the wind inputs, 40% is
lost in the losses inside the machinery of the windmill itself.
But the other 60% of the total energy input gets out as direct
pump power. If you only
have to input the 40% that was "lost", you get a coefficient
of performance of 60/40 = 1.5 COP.
There is no violation of energy conservation, but the system
did receive "extra" energy from the wind. 'That's
about as simple as it can be explained. You
cannot understand the MEG's operation unless you understand the
Aharonov-Bohm effect. In
that effect, if you hold the magnetic field energy (B-field) from a
magnetic source in a restricted local path, then in space around that
path nature will produce some magnetic energy in very special form, a
"magnetic vector potential" that is not swirling around but
"blowing straight". That
is a pure EM energy flow, in a special form of magnetic energy.
By "pulsing" that crazy kind of magnetic vector
potential flow, you make very large electrical fields.
Note that you do not furnish the energy in these fields, but
nature furnishes that. So
you can "put in a little" but change it rapidly, and nature
will "provide a lot" of that electrical field energy.
If you receive those electrical pulses in totally external
circuits, you can "catch a lot of excess energy" that you
did not have to put in. That's
it in a nutshell. Cheers, Tom
Bearden Subject:
Could you dummy-down your theories for me? |