| Subject: RE: Field-free A 
      potential in MEG  Date: Sat, 12 Jan 2002 10:48:57 -0600 
        
        Paul, 
        
          
        
        Just how we do it is 
        one of the things I'm not yet at liberty to release.  But any good 
        electrodynamicist these days, can calculate the normal A-potential and 
        also the field-free A-potential.  The field-free A-potential is still a
        vector potential, hence it has direction and motion as well as 
        magnitude.  The B-field is made from the A-potential, which is more 
        primary (the B-field, contrary to electrical engineering, does not and 
        cannot even exist as such in mass-free space, since it is defined in 
        terms of magnetically charged mass --- mass with magnetic poles).  So 
        when you reverse the magnet in the normal polarity sense, yes you have 
        reversed the A-potential, or the "made-from-it" B-field would not have 
        reversed.  That's just B = del cross A.  And for the E-field, E is just 
        E = - dA/dt. 
        
          
        
        I will admit that the 
        chief scientist of an important experimental group in a large company 
        was rather stunned at the type of output we were able to obtain.  The 
        MEG may look like just a transformer, but it is not.  It is a completely 
        different breed of cat. 
        
          
        
        To find how a 
        force-free A-potential actually behaves, one does lots of little 
        experiments with it.  Thereby one discovers some little "tricks" and 
        novel effects that allow one to use it.  As I said, I'm not at liberty 
        yet to reveal those little tricks; for one thing, they are not my 
        personal discovery, but that of the bench guys on the MEG project. 
        
          
        
        From any nonzero 
        potential, no matter how small, you can collect as much energy as you 
        have intercepting charges available to collect.  This is easily seen 
        with the electrostatic scalar potential (voltage) V.  the amount of 
        energy W in joules, collected from a single potential V, is just W = Vq, 
        where q is the amount of charges (in coulombs) that are present to 
        intercept and diverge the energy flows comprising the V.  The trick is 
        to make a little dipole (this is true either magnetically or 
        electrically) which has a static potential between its ends.  
        Electrically that is V, magnetically that is magnetostatic scalar 
        potential.  This dipole, once made, then must not be destroyed.  In 
        short, one must figure out how to collect lots of energy from the 
        potential so freely furnished by that dipole, then dissipate that 
        collected energy in the load and circuit losses, without using half the 
        collected energy to destroy the dipole.  That's about as plainly as I 
        can say it. 
        
          
        
        We moved into 
        magnetics experiments about a decade ago because of a compelling 
        feature: Running the return flux back through the source dipole of a 
        permanent magnet does not destroy the dipole, as contrasted to the 
        return current in an electrical circuit which is forcibly rammed back 
        through the source dipole in the generator and does destroy that dipole 
        (hence the potential that is potentializing the external circuit).  In 
        the magnet, the materials "lock in" the charges (the poles) so that they 
        cannot physically disperse. 
        
          
        
        Notice that what I 
        said is NOT adequately covered in conventional circuit theory, no matter 
        at what level applied.  The standard circuit theory prohibits and 
        excludes all COP>1.0, because it prescribes circuits which always use 
        half their collected energy to kill that source dipole furnishing the 
        potentialization (the potential energy) to the external circuit for it 
        to intercept, catch, and use.  Unless this "use half the collected 
        energy to destroy the source dipole" function of the standard 
        closed-current-loop circuit can be violated, all one's efforts will fail 
        and his circuits will never produce overunity performance, no matter how 
        much energy he collects in his external circuit. 
        
          
        
        That's about as 
        straightforward as I can say it.  As inventors and in a --- hopefully 
        --- commercial enterprise 
        eventually, we cannot release the "kit of parts" and actual "kit 
        assembly and tuning instructions" ahead of securing patent rights,  if 
        we wish to retain our patent rights.  I do get a few tirades from 
        misunderstanding folks who insist we should just "give it away".  My 
        response to them is simple:  They ask that the five of us who invented 
        the MEG just "give away" the results of about 10 years very hard work of 
        the group.  I ask them to show me that they practice what they preach; 
        we will be happy to receive their own wages for the last 10 to 50 
        manyears, as a "gift" to the project to show they do what they 
        prescribe. 
        
          
        
        Haven't had a single 
        taker on that suggestion yet!  Apparently lots of folks advocate one 
        thing, while actually practicing another. 
        
          
        
        So one must keep one's 
        sense of humor. In the patenting etc. business, there is a prescribed 
        procedure which any person or group has to comply with.  We have already 
        released far more information -- real, hard, technical information -- 
        than most other inventors have ever released on their overunity 
        systems.  There are two very rigorous papers in Foundations of Physics 
        Letters, e.g., showing exactly how the energy is received from the 
        active vacuum.  And the rigorous theory for it is there in those two 
        papers. 
        
          
        
        Hang in there and best 
        wishes, 
        
          
        
        Tom Bearden 
        
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