| Date: Mon, 7 Jan 2002 10:40:32
-0600
Dear Paul,
Even in ordinary
electromagnetics, we are permitted (by the model's representation of the
laws of nature) to freely change voltage (potential) at will. In real
life it may cost us a little "switching" energy to run the switching
process, but we can get enormous potential energy "for free" whenever we
wish. So getting the energy out of the vacuum and available, is not the
problem! Every circuit already does that in spades.
The problem is then in
discharging this "nearly free" potential energy into a load to do work,
without simultaneously killing the process that is giving us the free
potential.
In a circuit, the
source dipole (as in the generator or battery, etc.) usually is what
gives us the extra potential energy. Note the definition of potential
phi (or V, as electrical engineers use it). It is "joules per
collecting coulomb". So from any finite potential (voltage), the only
limitation on how much energy you can collect from it, is a matter of
how much collecting charge q you allow it to flow onto or around or
over. Each charge diverges a bit of it, to become "excited" or
"potentialized" to the intensity of the potential at that point.
But then comes the
problem. We are all taught to use the ubiquitous closed-current loop
circuit. This beast passes all spent current in the external circuit,
right back through the source dipole in the generator or battery,
against the dipole. It is easy to show that precisely one-half the
entire EM energy intercepted and "caught" in the external circuit from
that source dipole's potential, is then dissipated only to destroy the
dipole that is providing the potential energy in the first place.
The other half is
dissipated in the external circuit in the loads and losses. Hence less
than half the caught energy is used to power the load, while fully half
is used to kill that dipole. We then have to put in some more energy to
force the charges in the generator or battery back apart again and form
the source dipole.
But the ubiquitous
closed current loop circuit requires us to kill the energy source (the
source dipole, once made) faster than we power the load. That kind of
circuit can never exhibit COP>1.0, but is always COP<1.0.
So in your arrangement
(and thousands of others), we can indeed step up the voltage, nearly for
free, to a much higher voltage. It's called a step-up transformer. But
the "free energy" problem is in what is done with it after that.
Best wishes and good
luck in your studies,
Tom Bearden
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